In ΔJKL, overline{JL}
JL
is extended through point L to point M, text{m}angle JKL = (3x-16)^{circ}m∠JKL=(3x−16)
∘
, text{m}angle LJK = (2x+15)^{circ}m∠LJK=(2x+15)
∘
, and text{m}angle KLM = (8x-19)^{circ}m∠KLM=(8x−19)
∘
. Find text{m}angle LJK. m∠LJK.